LeetCode The Hard Way
0000 - 0099

0098 - Validate Binary Search Tree (Medium)

https://leetcode.com/problems/validate-binary-search-tree/

Problem Statement

Given the root of a binary tree, determine if it is a valid binary search tree (BST).

A valid BST is defined as follows:

The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greater than the node's key. Both the left and right subtrees must also be binary search trees.

Example 1:

Input: root = [2,1,3]
Output: true

Example 2:

Input: root = [5,1,4,null,null,3,6]
Output: false
Explanation: The root node's value is 5 but its right child's value is 4.

Constraints

  • The number of nodes in the tree is in the range [1, 104].
  • -231<=Node.val<=23112^31 <= Node.val <= 2 ^ 31 - 1

Approach 1: Preorder Traversal

Time Complexity: O(n)O(n)

Space Complexity: O(n)O(n) for recursive stack space

Written by@dhanu084
class Solution:
    def isValidBST(self, root: Optional[TreeNode]) -> bool:

        def validate(root, left, right):
            if root is None:
                return True
            # Validate the condition for each subtree
            if root.val <= left or root.val >= right:
                return False
            # all subtrees left of root should be less than right so pass root.val as right
            left = validate(root.left, left, root.val)
            # all subtrees right of root should be greater than right so pass root.val as left
            right = validate(root.right, root.val, right)
            # only if left and right subtrees are valid return true
            return left and right
        # pass -inf as the left minimum and inf as right maximum initially
        return validate(root, -inf, inf)

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